The triangle and the angles |
A + B = 100
B + C = 120
The sum of angles in a triangle is 180 degrees.
A + B + C = 180
Substitute in this formula the sum of two angles and find the third angle:
100 + C = 180
C = 180 - 100
C = 80
The second sum of the angles substitute angle C:
B + 80 = 120
B = 120 - 80
B = 40
The first sum of angles substitute angle B:
A + 40 = 100
A = 100 - 40
A = 60
A: The angles of the triangle are equal: A=60 degrees, B=40 degrees, C=80 degrees.
If we substitute in the second sum angles of a triangle, then the solution would be:
A + 120 = 180
A = 180 - 120
A = 60
60 + B = 100
B = 100 - 60
B = 40
60 + 40 + C = 180
C = 180 - 60 - 40
C = 80
The third variant of the decision:
We find the angle A of the first sum.
A + B = 100
A = 100 - B
We find the angle C of the second sum.
B + C = 120
C = 120 - B
Substitute the found angles to the general formula:
A + B + C = 180
(100 - B) + B + (120 - B) = 180
100 - B + B + 120 - B = 180
B - 2B = 180 - 100 - 120
-B = -40
B = 40
A = 100 - 40
A = 60
C = 120 - 40
C = 80
Conclusion: if the problem is solved correctly, the result does not depend on the method of solution.
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